Commit e4fa4e0f authored by Bryce Hepner's avatar Bryce Hepner
Browse files

just had to walk back one thing

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BryceCheckpoint.py

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+464 −0
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# %%
import numpy as np
from matplotlib import pyplot as plt
from itertools import product
import os
import sys
from PIL import Image
from scipy.optimize import minimize,linprog
import time
import seaborn as sns
from sklearn.neighbors import KernelDensity
import pandas as pd
from collections import Counter
import time
import numpy.linalg as la

# %%
def file_extractor(dirname="images"):
    files = os.listdir(dirname)
    scenes = []
    for file in files:
        if file == '.DS_Store':
            continue
        else:
            scenes.append(os.path.join(dirname, file))
    return scenes

def image_extractor(scenes):
    image_folder = []
    for scene in scenes:
        files = os.listdir(scene)
        for file in files:
            if file[-5:] != ".tiff" or file[-7:] == "_6.tiff":
                continue
            else:
                image_folder.append(os.path.join(scene, file))
    return image_folder #returns a list of file paths to .tiff files in the specified directory given in file_extractor

def im_distribution(images, num):
    """
    Function that extracts tiff files from specific cameras and returns a list of all
    the tiff files corresponding to that camera. i.e. all pictures labeled "_7.tiff" or otherwise
    specified camera numbers.
    
    Parameters:
        images (list): list of all tiff files, regardless of classification. This is NOT a list of directories but
        of specific tiff files that can be opened right away. This is the list that we iterate through and 
        divide.
        
        num (str): a string designation for the camera number that we want to extract i.e. "14" for double digits
        of "_1" for single digits.
        
    Returns:
        tiff (list): A list of tiff files that have the specified designation from num. They are the files extracted
        from the 'images' list that correspond to the given num.
    """
    tiff = []
    for im in images:
        if im[-7:-5] == num:
            tiff.append(im)
    return tiff

# %%
def predict_pix(tiff_image_path, difference = True):
    """
    This function predict the pixel values excluding the boundary.
    Using the 4 neighbor pixel values and MSE to predict the next pixel value
    (-1,1) (0,1) (1,1)  => relative position of the 4 other given values
    (-1,0) (0,0)        => (0,0) is the one we want to predict
    take the derivative of mean square error to solve for the system of equation 
    A = np.array([[3,0,-1],[0,3,3],[1,-3,-4]])
    A @ [a, b, c] = [-z0+z2-z3, z0+z1+z2, -z0-z1-z2-z3] where z0 = (-1,1), z1 = (0,1), z2 = (1,1), z3 = (-1,0)
    and the predicted pixel value is c.
    
    Input:
    tiff_image_path (string): path to the tiff file
    
    Return:
    image   ndarray(512 X 640): original image 
    predict ndarray(325380,): predicted image excluding the boundary
    diff.   ndarray(325380,): IF difference = TRUE, difference between the min and max of four neighbors exclude the boundary
                            ELSE: the residuals of the four nearest pixels to a fitted hyperplane
    error   ndarray(325380,): difference between the original image and predicted image
    A       ndarray(3 X 3): system of equation
    """
    image_obj = Image.open(tiff_image_path)    #Open the image and read it as an Image object
    image_array = np.array(image_obj)[1:,:].astype(int)    #Convert to an array, leaving out the first row because the first row is just housekeeping data
    # image_array = image_array.astype(int) 
    A = np.array([[3,0,-1],[0,3,3],[1,-3,-4]]) # the matrix for system of equation
    # where z0 = (-1,1), z1 = (0,1), z2 = (1,1), z3 = (-1,0)
    z0 = image_array[0:-2,0:-2]   # get all the first pixel for the entire image
    z1 = image_array[0:-2,1:-1]   # get all the second pixel for the entire image
    z2 = image_array[0:-2,2::]    # get all the third pixel for the entire image
    z3 = image_array[1:-1,0:-2]   # get all the forth pixel for the entire image
    
    # calculate the out put of the system of equation
    y0 = np.ravel(-z0+z2-z3)
    y1 = np.ravel(z0+z1+z2)
    y2 = np.ravel(-z0-z1-z2-z3)
    y = np.vstack((y0,y1,y2))
    
    # use numpy solver to solve the system of equations all at once
    #predict = np.floor(np.linalg.solve(A,y)[-1])
    predict = np.round(np.round((np.linalg.solve(A,y)[-1]),1))
    
    #Matrix system of points that will be used to solve the least squares fitting hyperplane
    points = np.array([[-1,-1,1], [-1,0,1], [-1,1,1], [0,-1,1]])
    
    # flatten the neighbor pixlels and stack them together
    z0 = np.ravel(z0)
    z1 = np.ravel(z1)
    z2 = np.ravel(z2)
    z3 = np.ravel(z3)
    neighbor = np.vstack((z0,z1,z2,z3)).T
    
    if difference:
        # calculate the difference
        diff = np.max(neighbor,axis = 1) - np.min(neighbor, axis=1)
    
    else:
        #Compute the best fitting hyperplane using least squares
        #The res is the residuals of the four points used to fit the hyperplane (summed distance of each of the 
        #points to the hyperplane), it is a measure of gradient
        f, diff, rank, s = la.lstsq(points, neighbor.T, rcond=None)
        diff = diff.astype(int)
    
    # calculate the error
    error = np.ravel(image_array[1:-1,1:-1])-predict
    
    return image_array, predict, diff, error, A

# %%
"""
this huffman encoding code is found online
https://favtutor.com/blogs/huffman-coding
"""

class NodeTree(object):
    def __init__(self, left=None, right=None):
        self.left = left
        self.right = right

    def children(self):
        return self.left, self.right

    def __str__(self):
        return self.left, self.right


def huffman_code_tree(node, binString=''):
    '''
    Function to find Huffman Code
    '''
    if type(node) is str:
        return {node: binString}
    (l, r) = node.children()
    d = dict()
    d.update(huffman_code_tree(l, binString + '0'))
    d.update(huffman_code_tree(r, binString + '1'))
    return d


def make_tree(nodes):
    '''
    Function to make tree
    :param nodes: Nodes
    :return: Root of the tree
    '''
    while len(nodes) > 1:
        (key1, c1) = nodes[-1]
        (key2, c2) = nodes[-2]
        nodes = nodes[:-2]
        node = NodeTree(key1, key2)
        nodes.append((node, c1 + c2))
        #reverse True, decending order
        sorted_nodes = sorted(nodes, key=lambda x: x[1], reverse=True)
    return sorted_nodes[0][0]

# %%
def huffman(tiff_image_path, num_bins=4, difference = True):
    """
    This function is used to encode the error based on the difference
    and split the difference into different bins
    
    Input:
    tiff_image_path     (string): path to the tiff file
    num_bins            (int): number of bins
    
    Return:
    list_dic    list (num_bins + 1): a list of dictionary
    image_array array (512, 640): original image
    new_error   array (512, 640): error that includes the boundary
    diff        array (510, 638): difference of min and max of the 4 neighbors
    boundary   (2300,): the boundary values after subtracting the very first pixel value
    predict    (325380,): the list of predicted values
    bins       (num_bins - 1,): a list of threshold to cut the bins
    A          (3 X 3): system of equation
    
    """
    # get the image_array, etc
    image_array, predict, diff, error, A = predict_pix(tiff_image_path, difference)
    
    # calculate the number of points that will go in each bin
    data_points_per_bin = diff.size // num_bins

    # sort the difference and create the bins
    sorted_diff = np.sort(diff.copy())
    bins = [sorted_diff[i*data_points_per_bin] for i in range(1,num_bins)]
    
    # get the boundary 
    boundary = np.hstack((image_array[0,:],image_array[-1,:],image_array[1:-1,0],image_array[1:-1,-1]))
    
    # take the difference of the boundary with the very first pixel
    boundary = boundary - image_array[0,0]
    
    #boundary is 1dim, so boundary[0] is just the first element
    boundary[0] = image_array[0,0]
    
    # huffman encode the boundary
    bound_vals_as_string = [str(i) for i in boundary]
    freq = dict(Counter(bound_vals_as_string))
    freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
    node = make_tree(freq)
    huffman_encoding_dict = huffman_code_tree(node)
    
    # create a list of huffman table
    huffman_encoding_list = [huffman_encoding_dict]
    n = len(bins)
    
    # loop through different bins
    for i in range (0,n):
        # the first bin
        if i == 0 :
            # get the point within the bin and huffman huffman_encoding_dict
            mask = diff <= bins[i]
            line_as_string = [str(i) for i in error[mask].astype(int)]
            freq = dict(Counter(line_as_string))
            freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
            node = make_tree(freq)
            huffman_encoding_dict = huffman_code_tree(node)
            huffman_encoding_list.append(huffman_encoding_dict)
            
        # the middle bins
        else:
            # get the point within the bin and huffman huffman_encoding_dict
            mask = diff > bins[i-1]
            new_error = error[mask]
            mask2 = diff[mask] <= bins[i]
            line_as_string = [str(i) for i in new_error[mask2].astype(int)]
            freq = dict(Counter(line_as_string))
            freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
            node = make_tree(freq)
            huffman_encoding_dict = huffman_code_tree(node)
            huffman_encoding_list.append(huffman_encoding_dict)
            
    # the last bin       
    # get the point within the bin and huffman huffman_encoding_dict
    mask = diff > bins[-1]
    line_as_string = [str(i) for i in error[mask].astype(int)]
    freq = dict(Counter(line_as_string))
    freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
    node = make_tree(freq)
    huffman_encoding_dict = huffman_code_tree(node)
    huffman_encoding_list.append(huffman_encoding_dict)

    # create a error matrix that includes the boundary (used in encoding matrix)
    new_error = np.copy(image_array)
    new_error[1:-1,1:-1] = np.reshape(error,(510, 638))
    keep = new_error[0,0]
    new_error[0,:] = new_error[0,:] - keep
    new_error[-1,:] = new_error[-1,:] - keep
    new_error[1:-1,0] = new_error[1:-1,0] - keep
    new_error[1:-1,-1] = new_error[1:-1,-1] - keep
    new_error[0,0] = keep
    
    diff = np.reshape(diff,(510,638))
    # return the huffman dictionary
    return huffman_encoding_list, image_array, new_error, diff, boundary, predict, bins, A
 


# %%
def encoder(error, list_dic, diff, bound, bins):
    """
    This function encode the matrix with huffman coding tables
    
    Input:
    error     (512, 640): a matrix with all the errors
    list_dic  (num_dic + 1,): a list of huffman coding table 
    bound     (2300,): the boundary values after subtracting the very first pixel value
    bins       (num_bins - 1,): a list of threshold to cut the bins
    
    Return:
    encoded   (512, 640): encoded matrix
    """
    # copy the error matrix (including the boundary)
    encoded = np.copy(error).astype(int).astype(str).astype(object)
    #diff = np.reshape(diff,(510,638))
    # loop through all the pixel to encode
    for i in range(encoded.shape[0]):
        for j in range(encoded.shape[1]):
            if i == 0 or i == encoded.shape[0]-1 or j == 0 or j == encoded.shape[1]-1:
                encoded[i][j] = list_dic[0][encoded[i][j]]
            elif diff[i-1][j-1] <= bins[0]:
                encoded[i][j] = list_dic[1][encoded[i][j]]
            elif diff[i-1][j-1] <= bins[1] and diff[i-1][j-1] > bins[0]:
                encoded[i][j] = list_dic[2][encoded[i][j]]
            elif diff[i-1][j-1] <= bins[2] and diff[i-1][j-1] > bins[1]:
                encoded[i][j] = list_dic[3][encoded[i][j]]
            else: 
                encoded[i][j] = list_dic[4][encoded[i][j]]

    return encoded

# %%
def decoder(A, encoded_matrix, list_dic, bins, use_diff):
    """
    This function decodes the encoded_matrix.
    Input:
    A               (3 X 3): system of equation
    list_dic        (num_dic + 1,): a list of huffman coding table 
    encoded_matrix  (512, 640): encoded matrix
    bins            (num_bins - 1,): a list of threshold to cut the bins
    
    Return:
    decode_matrix   (512, 640): decoded matrix
    """
    # change the dictionary back to list
    # !!!!!WARNING!!!! has to change this part, eveytime you change the number of bins
    the_keys0 = list(list_dic[0].keys())
    the_values0 = list(list_dic[0].values())
    
    the_keys1 = list(list_dic[1].keys())
    the_values1 = list(list_dic[1].values())
    
    the_keys2 = list(list_dic[2].keys())
    the_values2 = list(list_dic[2].values())
    
    the_keys3 = list(list_dic[3].keys())
    the_values3 = list(list_dic[3].values())
    
    the_keys4 = list(list_dic[4].keys())
    the_values4 = list(list_dic[4].values())
    
    #Matrix system of points that will be used to solve the least squares fitting hyperplane
    points = np.array([[-1,-1,1], [-1,0,1], [-1,1,1], [0,-1,1]])
    
    decode_matrix = np.zeros((512,640))
    # loop through all the element in the matrix
    for i in range(decode_matrix.shape[0]):
        for j in range(decode_matrix.shape[1]):
            # if it's the very first pixel on the image
            if i == 0 and j == 0:
                decode_matrix[i][j] = int(the_keys0[the_values0.index(encoded_matrix[i,j])])
            # if it's on the boundary
            elif i == 0 or i == decode_matrix.shape[0]-1 or j == 0 or j == decode_matrix.shape[1]-1:
                decode_matrix[i][j] = int(the_keys0[the_values0.index(encoded_matrix[i,j])]) + decode_matrix[0][0]
            # if not the boundary
            else:
                # predict the image with the known pixel value
                z0 = decode_matrix[i-1][j-1]
                z1 = decode_matrix[i-1][j]
                z2 = decode_matrix[i-1][j+1]
                z3 = decode_matrix[i][j-1]
                y0 = int(-z0+z2-z3)
                y1 = int(z0+z1+z2)
                y2 = int(-z0-z1-z2-z3)
                y = np.vstack((y0,y1,y2))
                if use_diff:
                    difference = max(z0,z1,z2,z3) - min(z0,z1,z2,z3)
                else:
                    
                    f, difference, rank, s = la.lstsq(points, [z0,z1,z2,z3], rcond=None) 
                    difference = difference.astype(int)
                    
                predict = np.round(np.round(np.linalg.solve(A,y)[-1][0],1))
                
                # add on the difference by searching the dictionary
                # !!!!!WARNING!!!! has to change this part, eveytime you change the number of bins
                if difference <= bins[0]:
                    decode_matrix[i][j] = int(the_keys1[the_values1.index(encoded_matrix[i,j])]) + int(predict)
                elif difference <= bins[1] and difference > bins[0]:
                    decode_matrix[i][j] = int(the_keys2[the_values2.index(encoded_matrix[i,j])]) + int(predict)
                elif difference <= bins[2] and difference > bins[1]:
                    decode_matrix[i][j] = int(the_keys3[the_values3.index(encoded_matrix[i,j])]) + int(predict)
                else:
                    decode_matrix[i][j] = int(the_keys4[the_values4.index(encoded_matrix[i,j])]) + int(predict)
                
                
    return decode_matrix.astype(int)

# %%
def compress_rate(image, new_error, diff, bound, list_dic, bins):
    '''
    This function is used to calculate the compression rate.
    Input:
    image      (512, 640): original image
    new_error  (512, 640): error that includes the boundary
    diff       (510, 638): difference of min and max of the 4 neighbors
    bound      (2300,): the boundary values after subtracting the very first pixel value
    list_dic   (num_dic + 1,): a list of huffman coding table 
    bins       (num_bins - 1,): a list of threshold to cut the bins
    
    Return:
    compression rate
    '''
    # the bits for the original image
    o_len = 0
    # the bits for the compressed image
    c_len = 0
    # initializing the varible 
    im = np.reshape(image,(512, 640))
    real_b = np.hstack((image[0,:],image[-1,:],image[1:-1,0],image[1:-1,-1]))
    original = image[1:-1,1:-1].reshape(-1)
    diff = diff.reshape(-1)
    error = new_error[1:-1,1:-1].reshape(-1)
    
    # calculate the bit for boundary
    for i in range(0,len(bound)):
        o_len += len(bin(real_b[i])[2:])
        c_len += len(list_dic[0][str(bound[i])])
    
    # calculate the bit for the pixels inside the boundary
    for i in range(0,len(original)):

        # for the original image
        o_len += len(bin(original[i])[2:])
        
        # check the difference and find the coresponding huffman table
        # !!!!!WARNING!!!! has to change this part, eveytime you change the number of bins
        if diff[i] <= bins[0]:
            c_len += len(list_dic[1][str(int(error[i]))])
            
        elif diff[i] <= bins[1] and diff[i] > bins[0]:
            c_len += len(list_dic[2][str(int(error[i]))])
            
        elif diff[i] <= bins[2] and diff[i] > bins[1]:
            c_len += len(list_dic[3][str(int(error[i]))])

        else: 
            c_len += len(list_dic[4][str(int(error[i]))])

    return c_len/o_len

# %%
scenes = file_extractor()
images = image_extractor(scenes)
list_dic, image, new_error, diff, bound, predict, bins, A = huffman(images[0], 4, False)
encoded_matrix = encoder(new_error, list_dic, diff, bound, bins)
reconstruct_image = decoder(A, encoded_matrix, list_dic, bins, False)
print(np.allclose(image, reconstruct_image))
print(len(list_dic))

# %%
compress_rate(image, new_error, diff, bound, list_dic, bins)

# %%
print(sys.getsizeof(encoded_matrix))
print(sys.getsizeof(reconstruct_image))

# %%