Commit 903776f0 authored by Nathaniel Callens's avatar Nathaniel Callens
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entropy

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%% Cell type:code id:14f74f21 tags:

``` python
import numpy as np
from matplotlib import pyplot as plt
from itertools import product
import os
import sys
from PIL import Image
from scipy.optimize import minimize,linprog
import time
import seaborn as sns
from sklearn.neighbors import KernelDensity
import pandas as pd
from collections import Counter
import time
```

%% Cell type:code id:c16af61f tags:

``` python
def file_extractor(dirname="images"):
    files = os.listdir(dirname)
    scenes = []
    for file in files:
        scenes.append(os.path.join(dirname, file))
    return scenes

def image_extractor(scenes):
    image_folder = []
    for scene in scenes:
        files = os.listdir(scene)
        for file in files:
            image_folder.append(os.path.join(scene, file))
    images = []
    for folder in image_folder:
        ims = os.listdir(folder)
        for im in ims:
            if im[-4:] == ".jp4" or im[-7:] == "_6.tiff":
                continue
            else:
                images.append(os.path.join(folder, im))
    return images #returns a list of file paths to .tiff files in the specified directory given in file_extractor

def im_distribution(images, num):
    """
    Function that extracts tiff files from specific cameras and returns a list of all
    the tiff files corresponding to that camera. i.e. all pictures labeled "_7.tiff" or otherwise
    specified camera numbers.

    Parameters:
        images (list): list of all tiff files, regardless of classification. This is NOT a list of directories but
        of specific tiff files that can be opened right away. This is the list that we iterate through and
        divide.

        num (str): a string designation for the camera number that we want to extract i.e. "14" for double digits
        of "_1" for single digits.

    Returns:
        tiff (list): A list of tiff files that have the specified designation from num. They are the files extracted
        from the 'images' list that correspond to the given num.
    """
    tiff = []
    for im in images:
        if im[-7:-5] == num:
            tiff.append(im)
    return tiff
```

%% Cell type:code id:aceba613 tags:

``` python
def plot_hist(tiff_list):
    """
    This function is the leftovers from the first attempt to plot histograms.
    As it stands it needs some work in order to function again. We will
    fix this later. 1/25/22
    """

    image = tiff_list
    image = Image.open(image)    #Open the image and read it as an Image object
    image = np.array(image)[1:,:]    #Convert to an array, leaving out the first row because the first row is just housekeeping data
    image = image.astype(int)
    A = np.array([[3,0,-1],[0,3,3],[1,-3,-4]]) # the matrix for system of equation
    z0 = image[0:-2,0:-2]   # get all the first pixel for the entire image
    z1 = image[0:-2,1:-1]   # get all the second pixel for the entire image
    z2 = image[0:-2,2::]    # get all the third pixel for the entire image
    z3 = image[1:-1,0:-2]   # get all the forth pixel for the entire image
    # calculate the out put of the system of equation
    y0 = np.ravel(-z0+z2-z3)
    y1 = np.ravel(z0+z1+z2)
    y2 = np.ravel(-z0-z1-z2-z3)
    y = np.vstack((y0,y1,y2))
    # use numpy solver to solve the system of equations all at once
    predict = np.floor(np.linalg.solve(A,y)[-1])
    # flatten the neighbor pixlels and stack them together
    z0 = np.ravel(z0)
    z1 = np.ravel(z1)
    z2 = np.ravel(z2)
    z3 = np.ravel(z3)
    neighbor = np.vstack((z0,z1,z2,z3)).T
    # calculate the difference
    diff = np.max(neighbor,axis = 1) - np.min(neighbor, axis=1)

    # flatten the image to a vector
    image = np.ravel(image[1:-1,1:-1])
    error = image-predict

    return image, predict, diff, error, A
```

%% Cell type:code id:6b965751 tags:

``` python
class NodeTree(object):
    def __init__(self, left=None, right=None):
        self.left = left
        self.right = right

    def children(self):
        return self.left, self.right

    def __str__(self):
        return self.left, self.right


def huffman_code_tree(node, binString=''):
    '''
    Function to find Huffman Code
    '''
    if type(node) is str:
        return {node: binString}
    (l, r) = node.children()
    d = dict()
    d.update(huffman_code_tree(l, binString + '0'))
    d.update(huffman_code_tree(r, binString + '1'))
    return d


def make_tree(nodes):
    '''
    Function to make tree
    :param nodes: Nodes
    :return: Root of the tree
    '''
    while len(nodes) > 1:
        (key1, c1) = nodes[-1]
        (key2, c2) = nodes[-2]
        nodes = nodes[:-2]
        node = NodeTree(key1, key2)
        nodes.append((node, c1 + c2))
        nodes = sorted(nodes, key=lambda x: x[1], reverse=True)
    return nodes[0][0]
```

%% Cell type:code id:b7561883 tags:

``` python
def huffman(image):
    origin, predict, diff, error, A = plot_hist(image)

    image = Image.open(image)
    image = np.array(image)[1:,:]    #Convert to an array, leaving out the first row because the first row is just housekeeping data
    image = image.astype(int)

    boundary = np.hstack((image[0,:],image[-1,:],image[1:-1,0],image[1:-1,-1]))
    boundary = boundary - image[0,0]
    boundary[0] = image[0,0]

    string = [str(i) for i in boundary]
    freq = dict(Counter(string))
    freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
    node = make_tree(freq)
    encode1 = huffman_code_tree(node)


    mask = diff <= 25
    string = [str(i) for i in error[mask].astype(int)]
    freq = dict(Counter(string))
    freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
    node = make_tree(freq)
    encode2 = huffman_code_tree(node)


    mask = diff > 25
    new_error = error[mask]
    mask2 = diff[mask] <= 40
    string = [str(i) for i in new_error[mask2].astype(int)]
    freq = dict(Counter(string))
    freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
    node = make_tree(freq)
    encode3 = huffman_code_tree(node)


    mask = diff > 40
    new_error = error[mask]
    mask2 = diff[mask] <= 70
    string = [str(i) for i in new_error[mask2].astype(int)]
    freq = dict(Counter(string))
    freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
    node = make_tree(freq)
    encode4 = huffman_code_tree(node)


    mask = diff > 70
    string = [str(i) for i in error[mask].astype(int)]
    freq = dict(Counter(string))
    freq = sorted(freq.items(), key=lambda x: x[1], reverse=True)
    node = make_tree(freq)
    encode5 = huffman_code_tree(node)


    new_error = np.copy(image)
    new_error[1:-1,1:-1] = np.reshape(error,(510, 638))
    keep = new_error[0,0]
    new_error[0,:] = new_error[0,:] - keep
    new_error[-1,:] = new_error[-1,:] - keep
    new_error[1:-1,0] = new_error[1:-1,0] - keep
    new_error[1:-1,-1] = new_error[1:-1,-1] - keep
    new_error[0,0] = keep


    #new_error = np.ravel(new_error)

    bins = [25,40,70]

    # return the huffman dictionary
    return encode1, encode2, encode3, encode4, encode5, np.ravel(image), error, new_error, diff, boundary, bins

scenes = file_extractor()
images = image_extractor(scenes)
encode1, encode2, encode3, encode4, encode5, image, error, new_error, diff, boundary, bins = huffman(images[0])
```

%% Cell type:code id:2eb774d2 tags:

``` python
def encoder(error, list_dic, diff, bound, bins):
    encoded = np.copy(error).astype(int).astype(str).astype(object)

    diff = np.reshape(diff,(510,638))

    for i in range(encoded.shape[0]):
        for j in range(encoded.shape[1]):
            if i == 0 or i == encoded.shape[0]-1 or j == 0 or j == encoded.shape[1]-1:
                encoded[i][j] = list_dic[0][encoded[i][j]]
            elif diff[i-1][j-1] <= bins[0]:
                encoded[i][j] = list_dic[1][encoded[i][j]]
            elif diff[i-1][j-1] <= bins[1] and diff[i-1][j-1] > bins[0]:
                encoded[i][j] = list_dic[2][encoded[i][j]]
            elif diff[i-1][j-1] <= bins[2] and diff[i-1][j-1] > bins[1]:
                encoded[i][j] = list_dic[3][encoded[i][j]]
            else:
                encoded[i][j] = list_dic[4][encoded[i][j]]


    return encoded
```

%% Cell type:code id:8eeb40d0 tags:

``` python
def decoder(A, encoded_matrix, encoding_dict):
    """
    Function that accecpts the prediction matrix A for the linear system,
    the encoded matrix of error values, and the encoding dicitonary.
    """
    the_keys = list(encode_dict.keys())
    the_values = list(encode_dict.values())
    error_matrix = encoded_matrix.copy()

    for i in range(error_matrix.shape[0]):
        for j in range(error_matrix.shape[1]):
            if i == 0 and j == 0:
                error_matrix[i][j] = int(the_keys[the_values.index(error_matrix[i,j])])

            elif i == 0 or i == error_matrix.shape[0]-1 or j == 0 or j == error_matrix.shape[1]-1:
                error_matrix[i][j] = int(the_keys[the_values.index(error_matrix[i,j])]) + error_matrix[0][0]
            else:
                """z0, z1, z2, z3 = error_matrix[i-1][j-1], error_matrix[i-1][j], \
                error_matrix[i-1][j+1], error_matrix[i][j-1]
                y = np.vstack((-z0+z2-z3, z0+z1+z2, -z0-z1-z2-z3))"""

                error_matrix[i][j] = int(the_keys[the_values.index(error_matrix[i,j])])

    return error_matrix.astype(int)
```

%% Cell type:code id:3e0e9742 tags:

``` python
encode1, encode2, encode3, encode4, encode5, image, error, new_error, diff, bound, bins = huffman(images[0])
encoded_matrix = encoder(np.reshape(new_error,(512,640)), [encode1, encode2, encode3, encode4, encode5], diff, bound, bins)

```

%% Cell type:code id:e6ea4f99 tags:

``` python
print(encoded_matrix)
```

%% Output

    [['01100010001' '11000110' '100101010' ... '101110011' '00010100'
      '1111000100']
     ['10011100' '100001' '111000' ... '10111011' '00111' '1111001101']
     ['10101111' '100100' '100000' ... '111100' '111000' '00010100']
     ...
     ['110001000' '100001' '111011' ... '1010010' '100000' '10011000']
     ['0100011101' '111010' '00110' ... '1000101' '1100100' '10011010']
     ['00100010' '110111101' '110110100' ... '00010010' '10100000'
      '110110101']]

%% Cell type:code id:0c07a23e tags:

``` python
```